When 80 ml of ozonised oxygen was heated until no further change was observed and then cooled to have the same initial temperature and pressure, the volume measured was 95 ml. What would be the voume, if 40 ml of the mixture of O2 and O3 was exposed to oil of turpentine?

(A) 15 ml

(B) 25 ml

(C) 20 ml

(D) 30 ml

Concept Videos :-

#6 | 16th Group

Concept Questions :-

group 16,preparation and properties

80 ml = 50 ml of O2 +30 ml of O3 gives 95 ml of O2.

 40 ml contains 25 ml of O2 +30 ml of O3 . The latter is absorbed by oil of turpentine.

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