NEET Chemistry Chemical Kinetics Questions Solved


The decomposition of A into product has value of k as 4.5×103s-1at 10°C and energy of activation 60 kJ mol-1.

At what temperature would k be  1.5 × 104 s-1

(A) 12°C                                         (B) 24°C  (C) 48°C                                         (D) 36°C

(B) k10=k283=4.5×103s-1, kT=1.5×104s-1,T=?Ea=60 kJ mol-1=60,000 J mol-1

Using Arrhenius equation, one can write

logkTk283=Ea2.303 R1283 K-1Tlog1.5×104s-14.5×103s-1=60000J mol-12.303×8.3J K-1mol-1T-283 K283 K×T

On solving this gives T=297K= 24°C

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