NEET Chemistry Chemical Kinetics Questions Solved


The inversion of cane sugar proceeds with half life of 500 minute at pH 5 for any concentration of sugar. However if pH = 6, the half life changes to 50 minute. The rate law expression for the sugar inversion can be written as 

(A) r = K[sugar]2 [H]6                                             

(B) r = K[sugar]1 [H]0

(C) r = K[sugar]0 [H+]6                                          

(D) r = K[sugar]0 [H+]1

(B). Since t1/2 does not depends upon the sugar concentration means it is first order respect to sugar concentration. t1/2 [sugar]1 .

                            t1/2 × an-1= k

t1/21t1/22=H+11-nH+21-n; 50050=10-510-61-n

10 = (10)1-n Hence n = 0

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