# NEET Chemistry Chemical Kinetics Questions Solved

1 mole of gas changes linearly from initial state (2 atm, 10 lt) to final state (8 atm, 4 lt). Find the value of rate constant, at the maximum temperature, that the gas can attain. Maximum rate constant is equal to 20 $se{c}^{-1}$ and value of activation energy is 40 kJ $mol{e}^{-1}$, assuming that activation energy does not change in this temperature range.

(A)

(B)

(C)

(D)

(C) Let the equation of straight line is P=mV+c

Now putting the values, we get P+V=12

From the ideal gas equation,

For T to be maximum $\frac{dT}{dV}$=0

V=6 lt, P=6 atm.

Value of

Now Putting the values of

we get,

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