NEET Chemistry Hydrogen Questions Solved


100 ml of a sample of hard water required 25.1 ml of 0.02 (N) H2SO4 for complete reaction. What is the hardness of the given water sample ? (sp. gravity of given water sample = 1 gm/ml)

(A) 200 ppm                                 

(B) 250 ppm

(C) 251 ppm                                 

(D) 258 ppm

c  25.1 ml of 0.02NH2SO4=25.1×0.02×10-3 equiv. of H2SO4       Now, 25.1×0.02×10-3 equiv. of H2SO4=25.1×0.02×10-3       equiv. of CaCO3=25.1×0.02×10-3×50 gm of CaCO3        Hardness of given water sample = 25.1×0.02×10-5×50×106=251 ppm.

Difficulty Level:

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