# NEET Chemistry Chemical Kinetics Questions Solved

The plot of log k versus $\frac{1}{T}$is linear with a slope of

(A) $\frac{{E}_{a}}{R}$

(B) $\frac{-{E}_{a}}{R}$

(C) $\frac{{E}_{a}}{2.303R}$

(D) $\frac{-{E}_{a}}{2.303R}$

(D) This is on the basis of Arrhenius equation which is

given us log K= log A

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