NEET Chemistry Chemical Kinetics Questions Solved

A graph plotted between log (t) 50% vs. log (a) concentration is a straight line. What conclusion can you draw from the given graph?

(a) n=1, t1/2 = 1/K.a

(b) n=2, t1/2 = 1/a

(c) n=1, t1/2 = 0.693/K

(d) None of the above

(c) t1/2 ∝ (a)1-n

or logt1/2 = Z(a)1-n

or logt1/2 =logZ + (1-n)loga

or y = c+mx

Thus, slope = m= 1-n or 1-n = 0

therfore n=1 and for I order reaction t1/2 =0.693/K

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