NEET Chemistry Chemical Kinetics Questions Solved


Rate equation for a second order reaction is:

(a) K = (2.303/t) log {a/(a-x)}

(b) K = (1/t) log {a/a(a-x)}

(c) K = (1/t) log {a/a(a-x)}

(d) K = (1/t2) log {a/(a-x)}

(c) dx/dt = K(a-x)2 is differential form of II order. Integrate it to get (c).

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