NEET Chemistry Chemical Kinetics Questions Solved


The activation energy for a reaction is 9.0 kcal/mol. The increase in the rate constant when its temperature is increased from 298K to 308K is:

(a) 10%

(b) 100%

(c) 50%

(d) 63%

(d) 2.303 log(K2/K1) = Ea/R{[T2-T1]/T1T2};

 2.303 log(K2/K1) = 9/2x10-3[10/298x308]

K2/K1 = 1.63; i.e ,63% increase 

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