A drop of solution (volume 0.05 mL) contains 3.0 x10-6 mole of H+. If the rate constant of disappearance of H+ is 1.0x10-7 mol litre sec?. How long would it take for H+ in drop to disappear?
(a) 6x10-8 sec
(c) 6x10-9 sec
Since rate constant = 1.0x10-7 mol litre sec
Zero order reaction.
For zero order t = x/K = concentration used/rate constant ....(i)
0.05ml has 3x10-6x103/0.05 = 0.06x10-1 mol/litre of H+
By Eq. (i), t = 0.6x10-1/1x107 = 6x10-9 second