NEET Chemistry Chemical Kinetics Questions Solved


The rate of disappearance of SO2 in the reaction; 2S02 +02 → 2S03 is 1.28 x10-3g/sec. Then the rate of formation of SO3 is:

(a) 0.64 x10-3 g/sec.

(b) 0.80x10-3 g/sec

(c) 1.28 x10-1 g/sec

(d) 1.60 x10-3 g/sec

(d) Rate of formation of SO3 = rate of disappearence of SO2

           = 1.28x10-3 g/sec = 1.28x10-3/64 M/sec (64 is the molecular weight of SO2)

           = (1.28x10-3/64)x80 g/sec = 1.60x10-3  g/sec

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