NEET Chemistry Chemical Kinetics Questions Solved


Hydrogenation of vegetable ghee at 250C reduces pressure of H2 from 2 atom to 1.2 atom in 50 minute. The rate of reaction in terms of molarity per second is:

(a)1.09 x 10-6

(b)1.09 x 10-5

(c)1.09 x 10-7

(d)1.09 x 10-8

 

(b) The change in molarity=n/V = P/RT = 0.8/(0.0821*273) = 0.0327

rate of reaction = change in molarity per sec = 0.0327/(50*60)=1.09*10-5 mil litre-1 sec-1

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