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Mol fraction of the component A in vapour phase is X1 and mol fraction of component A in liquid mixture is X2 then

(${\mathrm{P}}_{\mathrm{A}}^{0}$ = vapour pressure of pure A; ${\mathrm{P}}_{\mathrm{B}}^{0}$= vapour pressure of pure B),

then total vapour pressure of the liquid mixture is-

(a) $\frac{{\mathrm{P}}_{\mathrm{A}}^{0}{\mathrm{X}}_{2}}{{\mathrm{X}}_{1}}$

(b) $\frac{{\mathrm{P}}_{\mathrm{A}}^{0}{\mathrm{X}}_{1}}{{\mathrm{X}}_{2}}$

(c) $\frac{{\mathrm{P}}_{\mathrm{B}}^{0}{\mathrm{X}}_{1}}{{\mathrm{X}}_{2}}$

(d) $\frac{{\mathrm{P}}_{\mathrm{B}}^{0}{\mathrm{X}}_{2}}{{\mathrm{X}}_{1}}$