The Ksp (25°C) of sparingly soluble salt XY2(s) is 3.56X10-5(mol lit-1)3 and at 30°C the vapour pressure of its saturated solution in water is 31.78 mm Hg. Calculate the enthalpy change of the reaction.

XY2(s)          X2+(aq) + 2Y-(aq)

Given: Vapour pressure of pure water=31.82 mm Hg

(a) 42.5 kJ/mol.

(b) 32.1 kJ/mol.

(c) 24.5 kJ/mol.

(d) 52.5 kJ/mol.

Concept Questions :-

Relative Lowering of Vapour Pressure/ Vapour Pressure
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The vapoure pressure of a dilute aqueous solution of glucose is 750mm of mercury at 373K. The mole fraction of solute in the solution is-

(a) 1/10

(b) 1/76

(c) 1/7.6

(d) 1/35

Concept Questions :-

Relative Lowering of Vapour Pressure/ Vapour Pressure
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Which one of the folowing pairs of solution can we expect to be isotonic at the same temperature-

(a) 0.1 (M) urea and 0.1 (M) NaCl

(b) 0.1 (M) urea and 0.2 (M) MgCl2

(c) 0.1 (M) NaCl and 0.1 (M) Na2SO4

(d) 0.1 (M) Ca(NO3)2 and 0.1 (M) Na2SO4

Concept Questions :-

Osmosis and Osmotic Pressure
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Which of the following aqueous solution has osmotic pressure nearest to that an equimolar solution of K4[Fe(CN)6]?

(a) Na2SO4

(b) BaCl2

(c) Al2(SO4)3

(d) C12H22O11

Concept Questions :-

Osmosis and Osmotic Pressure
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The molar volume of liquid benzene (density= 0.877 g ml-1) increases by a factor of 2750 as it vapourises at 20°C. At 27°C when a non-volatile solute (that does not dissociate) is dissolved in 54.6cm3 of benzene, vapour pressure of this solution, is found to be 98.88 mm Hg. calculate the freezing point of the solution.

Given: Enthalpy of vapourisation of benzene(l)=394.57 Jg-1. Enthalpy of fusion of benzene (l) = 10.06 kJ mol-1 Molal depression constant for benzene=5.0 K kg mol-1.

(a) 177.65 K

(b) 277.65 K

(c) 517.65 K

(d) 237.15 K

Concept Questions :-

Depression of Freezing Point
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Calculate the depression in the freezing point of water when 10 g of CH3CH2CHClCOOH is added to 250 g of water.

Ka=1.4 X 10-3, Kf=1.86K kg mol-1

(a) 0.15°C

(b) 2.15°C

(c)1.15°C

(d)0.65°C

Concept Questions :-

Depression of Freezing Point
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The ratio of the vapour pressure of a solution to the vapour pressure of the solvent is

(a) Equal to the mole fraction of the solvent

(b) Proportional to the mole fraction of the solute

(c) Equal to the mole fraction of the solute

(d) None of the above

Concept Questions :-

Relative Lowering of Vapour Pressure/ Vapour Pressure
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Mole fraction of the component A in vapour phase is X1 and mole fraction of component A in liquid mixture is X2 then 

(PA0 = vapour pressure of pure A; PB0= vapour pressure of pure B),

then total vapour pressure of the liquid mixture is-

(a) PA0X2X1

(b) PA0X1X2

(c) PB0X1X2

(d) PB0X2X1

Concept Questions :-

Relative Lowering of Vapour Pressure/ Vapour Pressure
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pH of a 0.1 (M) mono basic is found to be 2. Hence osmotic pressure at given temperature T is-

1. 0.1 RT

2. 0.11RT

3. 1.1RT

4. 0.01RT

Concept Questions :-

Osmosis and Osmotic Pressure
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The vapour pressure of pure water at 298K is 23.76mm. The vapour pressure of a solution of sucrose(C12H22O11) in 5.56 moles of water is 23.392mm Hg. The mass of sucrose in the solution is

(a) 15 g

(b) 45 g

(c) 30 g

(d) 37.5 g

Concept Questions :-

Relative Lowering of Vapour Pressure/ Vapour Pressure
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