NEET Chemistry The Solid State Questions Solved


The anions (A) form hexagonal closest packing and atoms (C) occupy only 2/3 of octahedral voids in
it. then the general formula of the compound is-

(A) CA

(B) A2

(C) C2A3

(D) C3A2

Concept Videos :-

#9 | FCC Unit Cell: Packing Fraction
#20 | Rank of HP Unit Cell
#21 | Packing Fraction of HP Unit Cell
#24 | Density of Unit Cell

Concept Questions :-

Density/Formula/packing fraction/ Semiconductors

C) Hexagonal close packing contains 6 atoms per unit cell and hence the number of octahedral voids per unit cell is 6. 
Hence, number of A atoms per unit cell=6 and number of C atoms per unit cell=6 x 2/3=4
The formula of ionic compound is given as simplest formula and hence formula is C2A3

Difficulty Level:

  • 5%
  • 7%
  • 70%
  • 20%
Crack NEET with Online Course - Free Trial (Offer Valid Till September 21, 2019)