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As per Bohr model, the minimum energy (in eV) required to remove an electron from the ground state of doubly ionized Li atom (Z = 3) is 
(a) 1.51               (b) 13.6
(c) 40.8               (d) 122.4

(d) E=-Z2×13.6 eV=-9×13.6 eV=-122.4 eV
So ionisation energy = + 122.4 eV.

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