NEET Physics Thermodynamics Questions Solved


If heat given to a system is 6 kcal and work done is 6 kJ. Then change in internal energy is 

(1) 19.1 kJ

(2) 12.5 kJ

(3) 25 kJ

(4) Zero

(1) ΔQ=ΔU+ΔWΔU=ΔQΔW

=6×4.186=19.08kJ

19.1kJ

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