# NEET Physics Thermodynamics Questions Solved

If 150 J of heat is added to a system and the work done by the system is 110 J, then change in internal energy will be

(1) 260 J

(2) 150 J

(3) 110 J

(4) 40 J

(4) $\Delta Q=\Delta U+\Delta W$

$⇒\Delta U=\Delta Q-\Delta W=150-110=40\text{\hspace{0.17em}}J$

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