NEET Questions Solved

In a photoelectric experiment for 4000 Å incident radiation, the potential difference to stop the ejection is 2 V. If the incident light is changed to 3000 Å, then the potential required to stop the ejection of electrons will be

(a) 2 V                     (b) Less than 2 V
(c) Zero                   (d) Greater than 2 V

(d) According to Einstein's photoelectric equation

$\mathrm{E}={\mathrm{W}}_{0}+{\mathrm{K}}_{\mathrm{max}}⇒{\mathrm{V}}_{0}=\frac{\mathrm{hc}}{\mathrm{e}}\left[\frac{1}{\mathrm{\lambda }}-\frac{1}{{\mathrm{\lambda }}_{0}}\right]$

Hence if $\mathrm{\lambda }$ decreases ${\mathrm{V}}_{0}$ increases.

Difficulty Level:

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