Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statement is incorrect in this reaction?
(a) Evolved I2 is reduced
(b) CuI2 is formed
(c) Na2S2O3 is oxidised
(d) Cu2I2 is formed
(b) This liberated I2 is reduced and Na2S2O3 is oxidise.