For a transistor amplifier in common emitter configuration for load impedance of 1 kΩ (hfe = 50 and hoe = 25 μA/V) the current gain is 

(a) – 5.2                   (b) – 15.7

(c) – 24.8                  (d) – 48.78

(d) In common emitter configuration current gain

Ai=-hfe1+hoeRL=-501+25×10-6×103=-48.78

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