NEET Questions Solved


For the stationary wave y=4sinπx15cos(96πt), the distance between a node and the next antinode is 

(1) 7.5

(2) 15

(3) 22.5

(4) 30

(1) Comparing given equation with standard equation

y=2asin2πxλcos2πvtλ gives us 2πλ=π15λ=30

Distance between nearest node and antinodes = λ4=304=7.5

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