On adding A to the reaction at equilibrium,  AB(s)  A(g) + B(g), the new equilibrium concentration of A becomes double, the equilibrium concentration of B would become:

(a) 1/2 of its original value

(b) 1/4 of it s original value

(c) 1/8 of its original value

(d) twice of its original value

Concept Videos :-

#1 | Introduction

Concept Questions :-

Introduction To Equilibrium

(a) Kc = [A][B]/[AB];

         If [A] =2x[A]

        To have Kc constant [B] should be [B] x 1/2

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