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The solubility product of Hg2I2 is equal to:

(a) $\left[{\mathrm{Hg}}_{2}^{2+}\right]\left[{\mathrm{I}}^{-}\right]$

(b) $\left[{\mathrm{Hg}}_{}^{2+}\right]\left[{\mathrm{I}}^{-}\right]$

(c) $\left[{\mathrm{Hg}}_{2}^{2+}\right]\left[{\mathrm{I}}^{-}{\right]}^{2}$

(d) $\left[{\mathrm{Hg}}_{2}^{2+}{\right]}^{2}\left[{\mathrm{I}}^{-}{\right]}^{2}$