NEET Chemistry The Solid State Questions Solved


If NaCl is doped with 10-4 mol % of SrCl2, the concentration of cation vacancies will be (NA = 6.023 x 1023 mol-1)                                                                             

(a) 6.023 x 1015 mol-1                                            (b) 6.023 x 1016 mol-1

(c) 6.023 x 1017 mol-1                                            (d) 6.023 x 1014 mol-1                                     

(c) Doping of NaCl with 10-4 mol % of SrCl2 means, 100 moles of NaCl are doped with 10-4  mol of SrCl2.

... 1 mol of NaCl is doped with

                      SrCl2 = 10-4/100 = 10-6 mole

 As each Sr2+ ion introduces one cation vacancy.

... Concentration of cation vacancies

                             = 10-6 mol/mol of NaCl

                             = 10-6 x 6.023 x 1023 mol-1

                             = 6.023 x 1017 mol-1

                      

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