Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states?
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Concept Questions :-
For transition metal elements a general rule is = The max number of oxidation states = no. unpaired d-orbital electrons + the 2s electrons.
In 3d5 4s2 configuration
Number of unpaired d-electrons = 5
Hence Maximum number of oxidation states = 5+2=7
Such as Mn+7