Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states?

(a)3d3,4s2

(b)3d5,4s1

(c)3d5,4s2

(d)3d2,4s2

 

Concept Videos :-

#1 | Electronic configuration of elements
#2 | Predicting Group & Block No. of Elements
#7 | Transition Elements

Concept Questions :-

Electronic Configuration

(c)

For transition metal elements a general rule is = The max number of oxidation states = no. unpaired d-orbital electrons + the 2s electrons.

 

In 3d5 4s2 configuration

Number of unpaired d-electrons = 5

Hence Maximum number of oxidation states = 5+2=7

Such as Mn+7

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