If σ be the surface tension, the work done in breaking a big drop of radius R in n drops of equal radius is 

(a) Rn2/3σ                          (b) (n2/3-1)

(c) (n1/3-1)                    (d) 4πR2(n1/3-1)σ

Concept Questions :-

Surface tension
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A big drop of radius R is formed by 1000 small droplets of water, then the radius of small drop is

(a) R/2                                     (b) R/5
(c) R/6                                     (d) R/10

Concept Questions :-

Surface tension
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8000 identical water drops are combined to form a big drop. Then the ratio of the final surface energy to the initial surface energy of all the drops together is 
(a) 1 : 10                     (b) 1 : 15
(c) 1 : 20                      (d) 1 : 25

Concept Questions :-

Surface tension
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If work done in increasing the size of a soap film from 10 cm ×6 cm to 10 cm×11 cm is 2×10-4 J then the surface tension is

(a) 2×10-2 Nm-1              (b) 2×10-4 Nm-1

(c) 2×10-6 Nm-1              (d) 2×10-8 Nm-1

Concept Questions :-

Surface tension
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A mercury drop of radius 1cm is sprayed into 106 drops of equal size. The energy expended in joules is (surface tension of Mercury is 460×10-3 N/m)

(a) 0.057                      (b) 5.7

(c) 5.7×10-4                (d) 5.7×10-6

Concept Questions :-

Surface tension
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When two small bubbles join to form a bigger one, energy is

(a) Released                           (b) Absorbed
(c) Both (a) and (b)                (d) None of these

Concept Questions :-

Surface tension
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A film of water is formed between two straight parallel wires of length 10cm each separated by 0.5 cm. If their separation is increased by 1 mm while still maintaining their parallelism, how much work will have to be done (Surface tension of water =7.2×10-2 N/m)

(a) 7.22×10-6 Joule                         (b) 1.44×10-5 Joule

(c) 2.88×10-5 Joule                          (d) 5.76×10-5 Joule

Concept Questions :-

Surface tension
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A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is 0.465 J/m2
(a)23.4 μJ                              (b) 18.5 μJ
(c) 26.8 μJ                              (d) 16.8 μJ

Concept Questions :-

Surface tension
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Two small drops of mercury, each of radius r, coalesce to form a single large drop. The ratio of the total surface energies before and after the change is

1. 1:21/3                          2. 21/3 :1

3. 2:1                              4. 1:2

Concept Questions :-

Surface tension
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The work done in blowing a soap bubble of radius 0.2 m is (the surface tension of soap solution being 0.06 N/m)

(a) 192 π×10-4J                 (b) 280 π×10-4J

(c) 200 π×10-4J                 (d) None of these

Concept Questions :-

Surface tension
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