A liquid drop of diameter D breaks upto into 27 small drops of equal size. If the surface tension of the liquid is σ, then change in surface energy is 

(a) πD2σ                          (b) 2πD2σ

(c) 3πD2σ                         (d) 4πD2σ

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Surface tension
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One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is 

(a) 1000 : 1               (b) 1 : 1000
(c) 10 : 1                   (d) 1 : 10

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Surface tension
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If σ be the surface tension, the work done in breaking a big drop of radius R in n drops of equal radius is 

(a) Rn2/3σ                          (b) (n2/3-1)

(c) (n1/3-1)                    (d) 4πR2(n1/3-1)σ

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Surface tension
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A big drop of radius R is formed by 1000 small droplets of water, then the radius of small drop is

(a) R/2                                     (b) R/5
(c) R/6                                     (d) R/10

Concept Questions :-

Surface tension
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8000 identical water drops are combined to form a big drop. Then the ratio of the final surface energy to the initial surface energy of all the drops together is 
(a) 1 : 10                     (b) 1 : 15
(c) 1 : 20                      (d) 1 : 25

Concept Questions :-

Surface tension
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If work done in increasing the size of a soap film from 10 cm ×6 cm to 10 cm×11 cm is 2×10-4 J then the surface tension is

(a) 2×10-2 Nm-1              (b) 2×10-4 Nm-1

(c) 2×10-6 Nm-1              (d) 2×10-8 Nm-1

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Surface tension
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A mercury drop of radius 1cm is sprayed into 106 drops of equal size. The energy expended in joules is (surface tension of Mercury is 460×10-3 N/m)

(a) 0.057                      (b) 5.7

(c) 5.7×10-4                (d) 5.7×10-6

Concept Questions :-

Surface tension
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When two small bubbles join to form a bigger one, energy is

(a) Released                           (b) Absorbed
(c) Both (a) and (b)                (d) None of these

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Surface tension
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A film of water is formed between two straight parallel wires of length 10cm each separated by 0.5 cm. If their separation is increased by 1 mm while still maintaining their parallelism, how much work will have to be done (Surface tension of water =7.2×10-2 N/m)

(a) 7.22×10-6 Joule                         (b) 1.44×10-5 Joule

(c) 2.88×10-5 Joule                          (d) 5.76×10-5 Joule

Concept Questions :-

Surface tension
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A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is 0.465 J/m2
(a)23.4 μJ                              (b) 18.5 μJ
(c) 26.8 μJ                              (d) 16.8 μJ

Concept Questions :-

Surface tension
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