The force required to take away a flat circular plate of radius 2 cm from the surface of water, will be (the surface tension of water is 70 dyne/cm)

(a) 280 π dyne                      (b) 250 π dyne

(c) 140 π dyne                       (d) 210 π dyne

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Surface tension
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Surface tension may be defined as 

(a) The work done per unit area in increasing the surface area of a liquid under isothermal condition

(b) The work done per unit area in increasing the surface area of a liquid under adiabatic condition

(c) The work done per unit area in increasing the surface area of a liquid under both isothermal and adiabatic conditions

(d) Free surface energy per unit volume

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Surface tension
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Energy needed in breaking a drop of radius R into n drops of radii r is given by

(a) 4πT(nr2-R2)                        (b) 43π(r3n-R2)

(c) 4πT(R2-nr2)                         (d) 4πT(r2n+R2)

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Surface tension
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The potential energy of a molecule on the surface of liquid compared to one inside the liquid is  -
(a) Zero                                             (b) Smaller
(c) The same                                      (d) Greater

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Surface tension
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Two droplets merge with each other and forms a large droplet. In this process

(a) Energy is liberated

(b) Energy is absorbed

(c) Neither liberated nor absorbed

(d) Some mass is converted into energy

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Surface tension
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Radius of a soap bubble is 'r', surface tension of soap solution is T. Then without increasing the temperature, how much energy will be needed to double its radius

(a) 4πr2T                        (b) 2πr2T

(c) 12πr2T                       (d) 24πr2T

Concept Questions :-

Surface tension
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Work done in splitting a drop of water of 1 mm radius into 106 droplets is (Surface tension of water =72×10-3 J/m2)

(a) 9.58×10-5 J                  (b) 8.95×10-5 J

(c) 5.89×10-5 J                   (d) 5.98×10-5 J

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Surface tension
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The amount of work done in blowing a soap bubble such that its diameter increases from d to D is (T= surface tension of the solution)

(a) 4π(D2-d2)T                     (b) 8π(D2-d2)T

(c) π(D2-d2)T                        (d) 2π(D2-d2)T

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Surface tension
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A spherical drop of oil of radius 1 cm is broken into 1000 droplets of equal radii. If the surface tension of oil is 50 dynes/cm, the work done is 
(a) 18 ergs                     (b) 180 ergs
(c) 1800 ergs                  (d) 8000 ergs

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Surface tension
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A spherical liquid drop of radius R is divided into eight equal droplets. If surface tension is T, then the work done in this process will be

(a) 2πR2T                        (b) 3πR2T

(c) 4πR2T                         (d) 2πRT2

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Surface tension
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