Correct order of bond angle in given species is :
(d) NCl3>PCl3> SiO44->SbH3>H2Te
→ ;Hybridization of Si-sp3, bond angle=109°28'
∠Cl—N—Cl in NCl3 is greater than ∠Cl—P—Cl in PCl3 because
participation of s-orbital in hybridization decreases from NCl3 to PCl3
∠Cl—P—Cl in PCl3>∠H—Sb—H in SbH3, as in SbH3, bond pairs are formed by overlapping of almost pure p-orbitals.
∠H—Sb—H in SbH3<∠H—Te—H in H2Te because two lone pairs
are present on Te while at Sb there is one lone pair.