Cl2(g)+BaOH2  X(aq.)+BaCl2+H2O           X+H2SO4   Y+BaSO4                       Y >365K Z+H2O+O2

Y and Z are respectively :

(a) HCIO4, CIO2 

(b) HCIO3, CIO2

(c)  HCIO3, CIO6

(d) HCIO4, CI2O7

Concept Questions :-

group 17 ,preparation and properties
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Auto-oxidation of bleaching powder gives :

(a) only calcium chlorate                        (b) only calcium chloride

(c) only calcium hypochlorite                  (d) both (a) and (b) 

Concept Questions :-

group 17 ,preparation and properties
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The three elements X, Y and Z with electronic configuration shown below all form hydrides :

            Element                                     Electronic configuration      X                                                  1s22s22p2      Y                                                  1s22s22p63s1       Z                                                   1s22s22p63s23p63d104s24p5

Which set of properties match correctly with properties of the hydrides of these elements :

     Hydride of X                                      Hydride of Y                                   Hydride of Z

(a) Colourless gas insoluble in        Silver/grey solid reacts with H2O      Colourless gas forms a strong

        H2O                                        to form an alkali                                 acid in H2O

(b) Colourless liquid, no reaction    Silver/grey solid forms H2 and          Ionic solid with formula ZH

        with H2O                                  H2O                                

(c) Non-polar compound reacts       Silver/grey ionic solid with               Forms when water is added

     with Cl2 in light                            formula YH2                                 to phosphorus and element Z

(d) Colourless gas which burns        Silver/grey solid which reacts           Colourless, corrosive liquid

          with air                                     violently with acids                             at STP

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The incorrect order is :

(a) HF<HCl<HBr<Hl : Acidic strength(b) HF>HCl>HBr>Hl : Thermal stability(c) HF>HCl>HBr>Hl : Boiling point (d) HF>HCl>HBr>Hl : Bond dissociation enthalpy

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XeF2 and XeF6  are separately hydrolysed then;

(a) both give out O2

(b) XeF6 gives O2 and XeF2 does not

(c) XeF2 alone gives O2 

(d) Neither of them gives HF

 

 

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MF+XeF4 'A'  (M+=Alkali metal cation)

The state of hybridisation of the central atom in 'A' and shape of the species are:

(a) sp3d, TBP 

(b) sp3d3, distorted octahedral

(c)  sp3d2, pentagonal planar

(d) No compound formed at all

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XeF6 dissolves in anhydrous HF to give a good conducting solution which contains :

(a) H+ and XeF7- ion 

(b) HF2- and XeF5+ ions

(c) HXeF6+ and F- ions

(d) none of these

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Which of the following is not true about helium?

(a) It has the lowest boiling point 

(b) It has the highest first ionization energy

(c) It can diffuse through rubber and plastic material

(d) It can form clathrate compounds

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Which of the following is an uncommon hydrolysis product of XeF2 and XeF4?

(a) Xe

(b) XeO3

(c) HF

(d) O2

 

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SbF5 reacts with XeF4 to form an adduct. The shapes of cation and anion in the adduct are respectively:

(a) square planar, trigonal bipyramidal        (b) T-shaped, Octahedral

(c) square pyramidal, octahedral                 (d) square planar, octahedral

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