$\mathrm{In}, {\mathrm{Cl}}_2{\mathrm{O}}_6\left(\mathrm{l}\right)+\mathrm{HF} \underset{}{\to } \mathrm{P}+\mathrm{Q}$

$\mathrm{If} {\mathrm{H}}^{+} \mathrm{of} \mathrm{acid} \mathrm{HF} \mathrm{attaches} \mathrm{with} \mathrm{Q} \mathrm{then} \mathrm{correct} \mathrm{option} \mathrm{for} \mathrm{hybrization} \mathrm{of} \mathrm{Cl}-\mathrm{atom}$

$\mathrm{and} \angle \mathrm{OCIO} \mathrm{in} \mathrm{the} \mathrm{P} \mathrm{and} \mathrm{Q} \mathrm{ions} :$

$\left(\mathrm{a}\right) P\mathbf{:}s{p}^{\mathit{2}};>120°$

$\left(\mathrm{b}\right) Q\mathbf{:}s{p}^3; 109°28\text{'}$

$\left(\mathrm{c}\right) P\mathbf{:}s{p}^3;<109°28\text{'}$

$\left(\mathrm{d}\right) Q\mathbf{:}s{p}^3;>109°28\text{'}$

Bromine is commercially prepared from sea water by displacement reaction 

                       ${\mathrm{Cl}}_2+{\mathrm{Br}}^{‐}\left(\mathrm{aq}\right) \stackrel{}{\to } 2{\mathrm{Cl}}^{‐}\left(\mathrm{aq}\right)+{\mathrm{Br}}_2$

${\mathrm{Br}}_2$ gas thus formed is dissolved into solution of ${\mathrm{Na}}_2{\mathrm{CO}}_3$ and then pure ${\mathrm{Br}}_2$ is obtained by treatment of the solution with :

$\left(\mathrm{a}\right) \mathrm{Ca}(\mathrm{OH}{)}_2$

$\left(\mathrm{b}\right) \mathrm{NaOH}$

$\left(\mathrm{c}\right) {\mathrm{H}}_2{\mathrm{SO}}_4$

$\left(\mathrm{d}\right) \mathrm{HI}$

Cl₂(g) + Ba(OH)₂ → X(aq) + BaCl₂ + H₂O                      
X + H₂SO₄ → Y + BaSO₄                                              
Y \(\xrightarrow[]{\Delta \ > \ 365 \ K}\) Z + H₂O + O₂

Y and Z are respectively :
1. HClO₄, ClO₂
2. HClO₃, ClO₂
3. HClO₃, ClO₆
4. HClO₄, Cl₂O₇

Auto-oxidation of bleaching powder gives :

(1) only calcium chlorate                       

(2) only calcium chloride

(3) only calcium hypochlorite                 

(4) both (a) and (b) 

The three elements X, Y and Z with electronic configuration shown below all form hydrides :

            $\mathbf{Element}\mathbf{ } \mathbf{Electronic}\mathbf{ }\mathbf{configuration}$
$\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathrm{X} 1s^{\mathit{2}}2s^{\mathit{2}}2p^{\mathit{2}}$
$\mathrm{Y} 1s^{\mathit{2}}2s^{\mathit{2}}2p^{6}3s^{\mathit{1}}$
$\mathrm{Z} 1s^{\mathit{2}}2s^{\mathit{2}}2p^{\mathit{6}}3s^{\mathit{2}}3p^{\mathit{6}}3d^{\mathit{10}}4s^{\mathit{2}}4p^{\mathit{5}}$

Which set of properties match correctly with properties of the hydrides of these elements :

     Hydride of X                                      Hydride of Y                                   Hydride of Z

(a) Colourless gas insoluble in        Silver/grey solid reacts with ${\mathrm{H}}_2\mathrm{O}$      Colourless gas forms a strong

        ${\mathrm{H}}_2\mathrm{O}$                                        to form an alkali                                 acid in ${\mathrm{H}}_2\mathrm{O}$

(b) Colourless liquid, no reaction    Silver/grey solid forms ${\mathrm{H}}_2$ and          Ionic solid with formula $\mathrm{ZH}$

        with ${\mathrm{H}}_2\mathrm{O}$                                  ${\mathrm{H}}_2\mathrm{O}$                                

(c) Non-polar compound reacts       Silver/grey ionic solid with               Forms when water is added

     with ${\mathrm{Cl}}_2$ in light                            formula ${\mathrm{YH}}_2$                                 to phosphorus and element Z

(d) Colourless gas which burns        Silver/grey solid which reacts           Colourless, corrosive liquid

          with air                                     violently with acids                             at STP

The incorrect order is :

$\left(\mathrm{a}\right) \mathrm{HF}<\mathrm{HCl}<\mathrm{HBr}<\mathrm{Hl} \mathbf{:}\mathbf{ }\mathrm{Acidic} \mathrm{strength}$
$\left(\mathrm{b}\right) \mathrm{HF}>\mathrm{HCl}>\mathrm{HBr}>\mathrm{Hl} \mathbf{:}\mathbf{ }\mathrm{Thermal} \mathrm{stability}$
$\left(\mathrm{c}\right) \mathrm{HF}>\mathrm{HCl}>\mathrm{HBr}>\mathrm{Hl} \mathbf{:}\mathbf{ }\mathrm{Boiling} \mathrm{point}$
$\left(\mathrm{d}\right) \mathrm{HF}>\mathrm{HCl}>\mathrm{HBr}>\mathrm{Hl} \mathbf{:}\mathbf{ }\mathrm{Bond} \mathrm{dissociation} \mathrm{enthalpy}$

The correct statement among the following  is when ${\mathrm{XeF}}_2 \mathrm{and} {\mathrm{XeF}}_6$ are separately hydrolyzed;

$1. \mathrm{Both} \mathrm{give} \mathrm{out} {\mathrm{O}}_2$

$2. {\mathrm{XeF}}_6 \mathrm{gives} {\mathrm{O}}_2 \mathrm{and} {\mathrm{XeF}}_2 \mathrm{does} \mathrm{not}$

$3. {\mathrm{XeF}}_2 \mathrm{alone} \mathrm{gives} {\mathrm{O}}_2$

$4. \mathrm{Neither} \mathrm{of} \mathrm{them} \mathrm{gives} \mathrm{HF}$

${\mathrm{XeF}}_6$ dissolves in anhydrous $\mathrm{HF}$ to give a good conducting solution that contains-

1. H⁺ and \(XeF_{7}^{-}\) ions
2. \(HF_{2}^{-}\) and \(XeF_{5}^{+}\) ions
3. \(HXeF_{6}^{+}\) and F^- ions
4. None of the above

Which of the following statements about helium is false?

1. It has the lowest boiling point 

2. It has the highest first ionization energy

3. It can diffuse through rubber and plastic material

4. It can form clathrate compounds

Which of the following is an uncommon hydrolysis product of ${\mathrm{XeF}}_2 \mathrm{and} {\mathrm{XeF}}_4$?

$\left(\mathrm{a}\right) \mathrm{Xe}$

$\left(\mathrm{b}\right) {\mathrm{XeO}}_3$

$\left(\mathrm{c}\right) \mathrm{HF}$

$\left(\mathrm{d}\right) {\mathrm{O}}_2$