NEET Questions Solved


Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be 

(a) 0.6 mole

(b) 0.4 mole

(c) 7.5 moles

(d) 0.2 mole

(1) 0.6

10FeC2O4 + 6KMnO4 + 24H2SO----> 3K2SO4+ 6MnSO+  5Fe2(SO4)3 + 24H2O + 20CO2

So we see that  6 moles of KMnO4 is required to oxidize 10 moles of  FeC2O4  Then, 1 mole of FeC2O4 would be oxidized by = ?    6/10 = 0.6

Video Solution:

Difficulty Level:

  • 39%
  • 29%
  • 18%
  • 16%
Crack NEET with Online Course - Free Trial (Offer Valid Till August 26, 2019)