Two oxides of nitrogen, $\mathrm{NO}$ and ${\mathrm{NO}}_2$ are allowed to react together at $243°<mspace\; width="1em"></mspace>\mathrm{K}$ and form a coloured compound of nitrogen (X). When compound (X) reacts with water to yield another compound of nitrogen (Y). The shape of the anion of (Y) molecule is :

(a) triangular planar                              (b) triangle pyramidal

(c) tetrahedron                                      (d) square planar 

Consider the following sequence of reaction.

$\mathrm{Na}+{\mathrm{NH}}_3\left(\mathrm{g}\right)\underset{}{\to }\left[\mathrm{X}\right]\stackrel{{\mathrm{N}}_2\mathrm{O}}{\to }\left[\mathrm{Y}\right]\stackrel{\mathrm{Heat}}{\to }\underset{\mathrm{Gas}<mspace\; width="1em"></mspace>\mathrm{Pure}}{\left[\mathrm{Z}\right]}$

Identify [Z] gas :

$\left(\mathrm{a}\right)<mspace\; width="1em"></mspace>{\mathrm{N}}_2$

$\left(\mathrm{b}\right)<mspace\; width="1em"></mspace>{\mathrm{NH}}_3$

$\left(\mathrm{c}\right)<mspace\; width="1em"></mspace>{\mathrm{O}}_2$

$\left(\mathrm{d}\right)<mspace\; width="1em"></mspace>{\mathrm{H}}_2$

Which of the following statements is true? 

Which of the following on heating produces ${\mathrm{NO}}_2$?

(a) ${\mathrm{NaNO}}_3$                               (b) ${\mathrm{AgNO}}_3$

(c) ${\mathrm{NH}}_4{\mathrm{NO}}_3$                              (d) ${\mathrm{NH}}_4{\mathrm{NO}}_2$

$\mathrm{A}+{\mathrm{H}}_2\mathrm{O}\stackrel{}{\to }\mathrm{B}+\mathrm{HCl}$
$\mathrm{B}+{\mathrm{H}}_2\mathrm{O}\stackrel{}{\to }\mathrm{C}+\mathrm{HCl}$

Compound (A),(B) and (C) will be respectively :

(a) ${\mathrm{PCl}}_5,<mspace\; width="1em"></mspace>{\mathrm{POCl}}_3,<mspace\; width="1em"></mspace>{\mathrm{H}}_3{\mathrm{PO}}_3$                 (b) ${\mathrm{PCl}}_5,<mspace\; width="1em"></mspace>{\mathrm{POCl}}_3,<mspace\; width="1em"></mspace>{\mathrm{H}}_3{\mathrm{PO}}_4$

(c) ${\mathrm{SOCl}}_2,<mspace\; width="1em"></mspace>{\mathrm{POCl}}_3,<mspace\; width="1em"></mspace>{\mathrm{H}}_3{\mathrm{PO}}_3$               (d) ${\mathrm{PCl}}_3,<mspace\; width="1em"></mspace>{\mathrm{POCl}}_3,<mspace\; width="1em"></mspace>{\mathrm{H}}_3{\mathrm{PO}}_4$

Which of the following is in the correct sequence?

[For the correct order mark (T) and for the incorrect order mark (F)]:

In which of the following compounds hydrolysis takes place through ${\mathrm{S}}_{{\mathrm{N}}^1}$ and ${\mathrm{S}}_{{\mathrm{N}}^2}$ mechanism respectively?

(a) ${\mathrm{NF}}_3,<mspace\; width="1em"></mspace>{\mathrm{NCl}}_3$                       

(b) ${\mathrm{P}}_4{\mathrm{O}}_{10},<mspace\; width="1em"></mspace>{\mathrm{SiCl}}_4$

(c) ${\mathrm{SF}}_4,<mspace\; width="1em"></mspace>{\mathrm{TeF}}_6$                       

(d) ${\mathrm{SiCl}}_4,<mspace\; width="1em"></mspace>{\mathrm{SiF}}_4$ 

Incorrect statement regarding PH₃ is:

1. It is produced by the hydrolysis of Ca₃P₂${\mathrm{}}_{}$

2. It gives a black ppt, Cu₃P₂ with a CuSO₄ solution.

3. It spontaneously burns in the presence of ${\mathrm{P}}_2{\mathrm{H}}_4$

4. It does not react with ${\mathrm{B}}_2{\mathrm{H}}_6$

The false statement regarding hydrides from the 15th group is:

A non-metal M forms ${\mathrm{MCl}}_3,<mspace\; width="1em"></mspace>{\mathrm{M}}_2{\mathrm{O}}_5<mspace\; width="1em"></mspace>\mathrm{and}<mspace\; width="1em"></mspace>{\mathrm{Mg}}_3{\mathrm{M}}_2$ but does not form ${\mathrm{MI}}_5$. Then incorrect statement regarding non-metal M is:

(a) M can form multiple bond

(b) M is of second period element 

(c) Atomicity of non-metal is 4

(d) The range of oxidation number for M is +5 to -3