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The amplitude of a particle executing SHM is 4 cm. At the mean position the speed of the particle is 16 cm/sec. The distance of the particle from the mean position at which the speed of the particle becomes $8\sqrt{3cm}\phantom{\rule{0ex}{0ex}}$ will be

(a)         $2\sqrt{3cm}$              (b)  $\sqrt{3cm}$

(c)         1 cm                   (d)  2 cm