NEET Questions Solved


A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and time period T. The speed of the pendulum at x=A2 will be

(a)      πA32                 (b)  πT

(c)     πA32T                  (c)  3π2AT

(a)         Velocity of a particle executing S.H.M. is given by

    v=wa2-x2 =2πTA2-A24=2πT3A24=πA3T

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