# NEET Chemistry The p-Block Elements (XII) Questions Solved

BOARD

Account for the following :

(a) Phosphorus shows high tendency for catenation.

(b) ${F}_{2}$ is more reactive than $CI{F}_{3}$ but $CI{F}_{3}$ is more reactive than $C{l}_{2}$.

(c) Nitrogen is found in gaseous state.

(d) Decomposition of ozone molecule is a spontaneous process.

(e) $S{F}_{6}$ is inert towards hydrolysis.

(a) The bond strength of P-P is more tan N-N, therefore, phosphorus shows more tendency for catenation than nitrogen.

(b) Because the bond between Cl-F is weaker than the bond between Cl-Cl due to less effective overlapping of orbitals of Cl-F than Cl-Cl.

The ${F}_{2}$ is most reactive due to its high electrode potential.

(c) Due to small size and high electronegativity nitrogen forms $p\pi -p\pi$ multiple bonds, which are held together by weak Van-der Waal's forces of attraction which can be easily broken. Hence ${N}_{2}$ exists as a gas at room temperature.

(d) Because ${O}_{3}$ is thermodynamically unstable and its decomposition results in liberation of heat          ($∆H$ is -ve) and increase in entropy  so $∆G$ becomes -ve and process becomes spontaneous.

(e) In $S{F}_{6},$ S is protected by 6F atoms and does not allow ${H}_{2}O$ molecules to attach on it. So $S{F}_{6}$ inerts towards hydrolysis.

Difficulty Level:

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