(a) Draw the structures of the following :
(i) (s) (ii)
(b) Explain the following observations :
(i) Ammonia has a higher boiling point than phosphine.
(ii) Helium does not form any chemical compound.
(iii) Bi (V) is a stronger oxidising agent than Sb (V).
Shape : Pyramidal
Angle : The angle O-S-O is greater than
(b) (i) Due to intermolecular H-bonding in it has higher boiling point than which does not have any H-bonding.
(ii) Because the ionization energy of Helium is very high and very high positive electrons gain enthalpy.
(iii) The stability of +5 oxidation state decreases and that of +3 state increases due to inert pair effect down the group therefore Bi(v) accepts two electrons and gets reduced to Bi(v).