# NEET Chemistry The p-Block Elements (XII) Questions Solved

BOARD

Account for the following:

(i) Sulphur in vapour form exhibits paramagnetic behaviour.

(ii) $SnC{l}_{4}$ is more covalent than $SnC{l}_{2}.$

(iii) ${H}_{3}P{O}_{2}$ is a stronger reducing agent than ${H}_{3}P{O}_{3}.$

(i) In vapour state sulphur partly exists as ${S}_{2}$ molecule which has two unpaired electrons in the antibonding II orbitals and hence exhibits paramagnetism.

(ii) $S{n}^{+4}$ in $SnC{l}_{4}$ has more polarising power than $SnC{l}_{2}$

(iii) ${H}_{3}P{O}_{2}$ contains two P-H bonds while ${H}_{3}P{O}_{3}$ contains only one P-H bond therefore ${H}_{3}P{O}_{2}$ is stronger reducing agent.

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