How would you account for the following:
(i) is more acidic than
(ii) The N-O bond in is shorter than the N-O bond in
(iii) Both stabilize high oxidation states but the ability of oxygen to stabilize the higher oxidation state exceeds that of fluorine.
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(i) Since the size of sulphur is more than oxygen, S-H bond length increases and hence bond dissociation energy of S-H is less than O-H. Therefore S-H easily loses and thus is more acidic than
(ii) The resonating structure of and show that in two bonds are sharing a double bond while in 3 bonds are sharing a double bond. That's why has shorter bond than that of
(iii) Oxygen stabilizes the highest oxidation state even more than fluorine.
Example : Highest fluoride of Mn is whereas highest oxide is . It is due to ability of oxygen to form multiple bonds with the metal atoms.