# NEET Chemistry The p-Block Elements (XII) Questions Solved

BOARD

Explain the following situations :

(i) In the structure of $HN{O}_{3}$ molecule, the N-O bond (121 pm) is shorter than N-Oh bond (140 pm).

(ii) $S{F}_{4}$ is easily hydrolysed whereas $S{F}_{6}$ is not easily hydrolysed.

(iii) $Xe{F}_{2}$ has a straight linear structure and not a bent angular structure.

(i)  In the structure the bond length of N-O is shorter due to formation of coordinate bond and double bond while in N-OH the bond is single covalent due to which its bond length is greater than other N-O bond.

(ii) In $S{F}_{4}$, due to less steric hindrance by four F atoms, ${H}_{2}O$ molecules can attack easily while in $S{F}_{6}$ the S atom is completely protected by six F atoms and does not allow ${H}_{2}O$ molecules to attack the S atom.

(iii) In $Xe{F}_{2}$ there are 2 bond pairs and 3 lone pairs and thus show $s{p}^{3}d$ hybridization. It has linear geometry.

Difficulty Level:

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