NEET Chemistry The Solid State Questions Solved

BOARD

If NaCl is doped with 10-3 mole percent SrCl2, what will be the concentration of cation vacancies? (NA = 6.02 × 1023 mol-1)

10-3 mol percent means 100 moles of NaCl are doped with 10-3 moles of SrCl2

 1 mole of NaCl is doped with SrCl2

10-3100 = 10-5 mole

Since each Sr2+ ion introduces one cation vacancy

 Concentration of cation vacancies

= 10-5 mol/mol of NaCl

= 10-5 × 6.02 × 1023 mol-1

= 6.02 × 1018 mol-1

Difficulty Level:

Crack NEET with Online Course - Free Trial (Offer Valid Till September 24, 2019)