# NEET Chemistry Chemical Kinetics Questions Solved

BOARD

(a) A reaction is second order in A and first order in B.

(i) Write the differential rate equation.

(ii) How is the rate affected on increasing the concentration of A three times?

(iii) How is the rate affected when the concentrations of both A and B are doubled?

(b) A first order reaction takes 40 minutes for 30% decomposition. Calculate t1/2 for this reaction (Given log 1.428 = 0.1548)

(a) (i) Differential rate equation :

$\frac{d\mathcal{x}}{dt}=K\left[A{\right]}^{2}\left[B\right]$

(ii) When concentration of A is increased to three times, the rate of reaction becomes 9 times

r=K[3A]2B

(iii)     r=K[2A]2[2B]

(b) Given :  Time, t = 40 minutes,   t1/2 =?

Let a = 100,            = 30% of 100 =30

Using the formula :

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