A reaction is of second order with respect to its reactant. How will its reaction rate be affected if the concentration of the reactant is (i)doubled (ii)reduced to half?
Since Rate =K[A]2
For second order reaction
Let [A] = a then Rate = Ka2
(i) If [A] = 2a then Rate = K(2a)2 = 4Ka2
Rate of reaction becomes 4 times
(ii) If [A] = then Rate = K
Rate of reaction will be