A reaction is of second order with respect to a reactant. How is its rate affected if the concentration of the reactant is (i) doubled (ii) reduced to half?
As Formula, r = K[R]2
(i) R' = 2R r = K[2R]2 = 4KR2
Rate becomes 4 times than original rate
(ii) R' =R r = K = R2
Rate becomes times of the original rate