A reaction is of first order in reactant A and of second order in reactant B. How is the rate of this reaction affected when
(i) the concentration of B alone is increased to three times
(ii) the concentration of A as well as B are doubled?
r = k[A]1 [B]2
(i) When concentration of B increases to 3 times, the rate of reaction becomes 9 times
r=KA(3B) 2 r = 9KAB2 = 9 times
(ii) r=K(2A)(2B) 2 r = 8KAB2 = 8 times