In a Geiger - Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 80, when an particle of 8 MeV energy impinges on it before it comes momentarily to rest and reverses its direction.
How will the distance of closest approach be affected when the kinetic energy of the is doubled?
If KE becomes twice then
i.e. distance of closest approach becomes half (1/2) marks