NEET Physics Alternating Current Questions Solved


An alternating voltage given by V = 140 sin314t is connected across a pure resistor

of 50Ω. Find

  (i) the frequency of the source 

  (ii) the rms current through the resistor

a) 2πv=314 rad s-1                                                          (1/2) marks

v = 50 Hz                                                                      (1/2) marks

b) irms=vrmsR where Vrms=V2                                          (1/2) marks

          = 1402×50=1.98 A 2A                                        (1/2) marks 

Difficulty Level:

Crack NEET with Online Course - Free Trial (Offer Valid Till September 21, 2019)