Distinguish between nuclear fission and fussion. Show how in

both of these processes energy is released.                            (3 marks)

Calculate the energy release in MeV in the deuterium-tritium

fusion reaction:

 H12+H13He24+n

Using the data:

m(H12)=2.014102 um(H13)=3.016049 um(H24)=4.002603 umn=1.008665 u1 u =931.5 MeV/c2

 

The breaking of heavy nucleus into smaller fragments is called nuclear

fission; the joining of lighter nuclei is to form a heavy nucleus is called

nuclear fusion.                                                                         (1/2+1/2 marks)

Binding energy per nucleon, of the daughter nuclei, in both processes, 

is more than that of the parent nuclei. The difference in binding energy

is released in the form of energy. In both processes some mass gets

converted into energy.                                                                (1/2 mark)

Alternatively:

In both processes, some mass gets converted into energy.

Energy Released

Q=[m(H12)+ m(H13)- m(He24)- m(n)]×931.5 MeV            (1/2 mark)

=[2.014102+ 3.016049-4.002603-1.008665] x 931.5 MeV    (1/2 mark)

=0.018883 x 931.5 MeV      

= 17.59 MeV                                                                      (1/2 mark)

Difficulty Level: