NEET Physics Thermodynamics Questions Solved

NEET - 2008

 

At 10°C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is 

(a) x

(b)383283x

(c)10110x

(d) 283383x

 

Writing ideal gas law 

                PV=nRTor      PV=mMRTor      PVm=1MRTor       Pρ=RTMor         ρP=1T       ρ1/P2ρ2/P1=T2T1         xρ1/P2=383283or           ρ2P2=283383x

    

Difficulty Level:

  • 9%
  • 34%
  • 20%
  • 39%
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