# NEET Physics Thermodynamics Questions Solved

NEET - 2008

At ${10}^{°}C$ the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At ${110}^{°}C$ this ratio is

(a) x

(b)$\frac{383}{283}x$

(c)$\frac{10}{110}x$

(d) $\frac{283}{383}x$

Writing ideal gas law

Difficulty Level:

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